The equation Tl2O3 + 6HCl -> 2TlCl3 + 3H2O

  1. The chemical equation above represents the chemical reaction between thallium(III) oxide (Tl2O3) and hydrochloric acid (HCl) to form thallium(III) chloride (TlCl3) and water (H2O).

  2. Reaction conditions: The reaction occurs under normal temperature and pressure conditions.

  3. Reaction process: Thallium(III) oxide (Tl2O3) reacts with 6 mol of hydrochloric acid (HCl) to produce 2 mol of thallium(III) chloride (TlCl3) and 3 mol of water (H2O).

  4. Phenomenon occurring: During the reaction process, thallium(III) oxide will dissolve in the hydrochloric acid solution, forming a solution of thallium(III) chloride and generating water.

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