The above equation describes the reaction process between potassium permanganate (KMnO4) and oxalic acid (H2C2O4) at a ratio of 5:8 to form potassium oxalate (K2C2O4), manganese sulfate (MnSO4) and water (H2O).
- Reaction conditions
This reaction occurs in an acidic environment.
- Reaction process
When KMnO4 and H2C2O4 meet in an acidic environment, KMnO4 is reduced to MnSO4, while H2C2O4 is oxidized to K2C2O4 and water. This is a redox reaction.
- Occurring phenomena
During the reaction process, the solution will change from the purple color of KMnO4 to the colorless of MnSO4.