The equation is 3KMnO4 + 2H2SO4 -> K2SO4 + 3MnSO4 + 2H2O + 5O2.

  1. Detailed information about the equation:

The above equation describes the oxidation process of potassium permanganate (KMnO4) in a strong acid environment (H2SO4) to produce potassium sulfate (K2SO4), manganese sulfate (MnSO4), water (H2O), and oxygen gas (O2).

  1. Reaction conditions:

This reaction requires a strong acid environment, provided by sulfuric acid (H2SO4). The reaction occurs at room temperature.

  1. The reaction process:

This process involves the oxidation of potassium permanganate (KMnO4) under the influence of sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4), manganese sulfate (MnSO4), water (H2O) and oxygen gas (O2). Potassium permanganate is oxidized from manganese (Mn+7) in KMnO4 down to manganese (Mn+2) in MnSO4, while oxygen from KMnO4 and H2O is released as oxygen gas (O2).

  1. Phenomena occurring:

During the reaction, we can observe the color change. Potassium permanganate is purple, but after the reaction, the solution will turn to a light pink color due to the formation of MnSO4. At the same time, we can also observe the release of oxygen gas.

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