The equation Fe2S3 + 9H2O2 -> 2FeSO4 + 6H2O.

1. Detailed Information about the Equation Fe₂S₃ + 9H₂O₂ -> 2FeSO₄ + 6H₂O

The above equation describes the reaction between Iron (III) sulfide (Fe₂S₃) and Hydrogen peroxide (H₂O₂) producing Iron (II) sulfate (FeSO₄) and water (H₂O).

2. Reaction Conditions

The reaction usually takes place at room temperature and standard pressure. However, the reaction rate can be accelerated by increasing the temperature or using a catalyst.

3. Reaction Process

• Reactants: Fe₂S₃ (Iron (III) sulfide) and H₂O₂ (Hydrogen peroxide)
• Products: FeSO₄ (Iron (II) sulfate) and H₂O (water)
• Reaction ratio: 1 mol of Iron (III) sulfide reacts with 9 mol of Hydrogen peroxide to produce 2 mol of Iron (II) sulfate and 6 mol of water.

4. Phenomena Occurring

When the reaction occurs, one can observe the color change from black (the color of Fe₂S₃) to light green (the color of FeSO₄). In addition, if the reaction takes place under high temperature conditions, the release of gas can be observed.