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Detailed information about the reaction Fe + 4CuSO4 -> 2Fe2(SO4)3 + 4Cu
The above equation describes the chemical reaction between iron (Fe) and copper sulfate (CuSO4) to form iron (III) sulfate (Fe2(SO4)3) and copper (Cu). This reaction indicates that iron has a stronger reducing property than copper, leading to the reduction of Cu2+ in copper sulfate solution to form copper metal, and simultaneously being oxidized to Fe3+, forming iron (III) sulfate. -
Reaction conditions
This reaction occurs under normal conditions of temperature and pressure. Iron needs to be in direct contact with the copper sulfate solution. -
Reaction process
When iron comes into contact with copper sulfate solution, the Fe2+ ions of iron will be oxidized to Fe3+ and simultaneously reduce the Cu2+ ions of copper sulfate to copper metal. -
Phenomena occurring
When the reaction occurs, brownish-red copper particles will appear on the surface of the iron. The initially blue copper sulfate solution gradually turns murky brown due to the formation of iron (III) sulfate.