The equation Cu(NO3)2 + 4H2S -> CuS + 4HNO3 + 4H2O

  1. Detailed information about the equation Cu(NO3)2 + 4H2S -> CuS + 4HNO3 + 4H2O:
    The above equation represents a chemical reaction between copper(II) nitrate (Cu(NO3)2) and hydrogen sulfide (H2S) to form copper sulfide (CuS), nitric acid (HNO3), and water (H2O).

  2. Reaction conditions:
    The reaction can occur under normal conditions, without specific requirements for temperature, pressure, or catalysts.

  3. Reaction process:

    • Step 1: The copper ions in copper(II) nitrate interact with the hydrogen sulfide compound, forming a new compound, copper sulfide.
    • Step 2: Once copper sulfide is formed, it will dissociate, producing copper ions and sulfide ions.
    • Step 3: The remaining hydrogen sulfide molecules will continue to react with the remaining nitrate ions, forming nitric acid and water.

  4. Observed phenomena:
    During the reaction, we can observe a clear phenomenon where the color of the solution changes due to the formation of black copper sulfide.

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