The equation Cu + 2K2Cr2O7 + H2SO4 -> CuSO4 + 2Cr2(SO4)3 + K2SO4 + H2O

1. Detailed information about the chemical equation Cu + 2K₂Cr₂O₇ + H₂SO₄ -> CuSO₄ + 2Cr₂(SO₄)₃ + K₂SO₄ + H₂O:

This is a chemical equation describing the oxidation process of copper (Cu) by a redox reaction with potassium dichromate (K₂Cr₂O₇) in a sulfuric acid environment (H₂SO₄). The products of the reaction include copper sulfate (CuSO₄), chromium sulfate (Cr₂(SO₄)₃), potassium sulfate (K₂SO₄), and water (H₂O).

2. Reaction conditions:

The reaction takes place in a strong acidic environment (here it is H₂SO₄ environment), the temperature must be high enough.

3. Reaction process:

Initially, copper (Cu) is oxidized by potassium dichromate (K₂Cr₂O₇) in a sulfuric acid environment (H₂SO₄), creating Cu₂+ ions (this is CuSO₄ when combined with SO₄₂-). Potassium dichromate in this process is reduced to Cr₃+ ions (this is Cr₂(SO₄)₃ when combined with SO₄₂-). Water (H₂O) is formed due to the balance of the reaction.

4. Phenomena occurring:

When copper is allowed to react with a solution of potassium dichromate in a concentrated sulfuric acid environment, the color of the solution changes from the orange of K₂Cr₂O₇ to the blue of CuSO₄ and the blue-green of Cr₂(SO₄)₃.