The equation BaSO4 + 2KOH -> K2SO4 + Ba(OH)2

  1. Detailed information about the equation BaSO4 + 2KOH -> K2SO4 + Ba(OH)2

    • BaSO4, fully named as Barium Sulfate, is a colorless solid substance that is insoluble in water.
    • KOH, fully named as Potassium Hydroxide, is a white, odorless solid substance, highly soluble in water forming an alkaline solution.
    • K2SO4, fully named as Potassium Sulfate, is a white solid substance, soluble in water.
    • Ba(OH)2, fully named as Barium Hydroxide, is a colorless solid substance, soluble in water forming an alkaline solution.

  2. Reaction conditions: The reaction occurs at room temperature and standard pressure. BaSO4 needs to come into direct contact with KOH.

  3. Reaction process: Barium sulfate (BaSO4) reacts with potassium hydroxide (KOH) to form potassium sulfate (K2SO4) and barium hydroxide (Ba(OH)2).

  4. Occurring phenomena: Solid BaSO4 is decomposed, producing K2SO4 and Ba(OH)2. The resultant product can be observed as a white solid or alkaline solution.

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