The equation B2O3 + 6NaOH -> 2Na3BO3 + 3H2O

Detailed information about the reaction B₂O₃ + 6NaOH -> 2Na₃BO₃ + 3H₂O
This equation represents the reaction between boron trioxide (B₂O₃) and sodium hydroxide (NaOH) to form sodium borate (Na₃BO₃) and water (H₂O). This is a exchange reaction, in which the boron, sodium, oxygen and hydrogen atoms in the initial reactants are rearranged to form new compounds.

Reaction conditions
The reaction requires high temperature and appropriate catalyst to occur.

Reaction process
When boron trioxide and sodium hydroxide are mixed together and heated, they start to react. Boron atoms in boron trioxide combine with sodium and oxygen atoms in sodium hydroxide to form sodium borate. The remaining hydrogen atoms from sodium hydroxide combine with oxygen to form water.

Observed phenomena
During the reaction, boiling and evaporation can be observed. A large amount of heat is also released in this process. The initial white mixture turns light yellow after the reaction (the color of sodium borate).