The equation Al(NO3)3 + 3NaOH -> Al(OH)3 + 3NaNO3

  1. The chemical equation above describes the neutralization reaction between aluminum nitrate (Al(NO3)3) and sodium hydroxide (NaOH) to produce aluminum hydroxide (Al(OH)3) and sodium nitrate (NaNO3). One molecule of aluminum nitrate reacts with three molecules of sodium hydroxide to produce one molecule of aluminum hydroxide and three molecules of sodium nitrate.

  2. Reaction conditions: This reaction occurs at room temperature and standard pressure. Aluminum nitrate (Al(NO3)3) must be dissolved in water before encountering sodium hydroxide (NaOH).

  3. Reaction process: When aluminum nitrate and sodium hydroxide come into contact, the aluminum ion (Al3+) in aluminum nitrate reacts with the hydroxide ion (OH-) in sodium hydroxide to form aluminum hydroxide (Al(OH)3). Simultaneously, the sodium ion (Na+) in sodium hydroxide reacts with the nitrate ion (NO3-) in aluminum nitrate to form sodium nitrate (NaNO3).

  4. Phenomenon that occurs: During the reaction, we usually observe the appearance of white precipitate of aluminum hydroxide. At the same time, the solution also becomes acidic due to the presence of sodium nitrate.

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