The equation Al2S3 + 6H2O -> 2Al(OH)3 + 3H2S

  1. Detailed information about the equation Al2S3 + 6H2O -> 2Al(OH)3 + 3H2S

This equation illustrates the reaction process between aluminum sulfide (Al2S3) and water (H2O) to create aluminum hydroxide (Al(OH)3) and hydrogen sulfide (H2S). According to the law of conservation of mass, each 1 mol Al2S3 requires 6 mol H2O to produce 2 mol Al(OH)3 and 3 mol H2S.

  1. Reaction conditions

This reaction requires a suitable level of temperature and pressure. Typically, for this reaction, room temperature and standard pressure are the best conditions.

  1. Reaction process

When aluminum sulfide comes into contact with water, it reacts to form aluminum hydroxide and hydrogen sulfide. This reaction occurs quite strongly and quickly, producing a large amount of heat.

  1. Observed phenomena

During the reaction process, there will be a bubbling phenomenon due to the escape of H2S gas. H2S is a gas with a distinctive foul odor (resembling rotten eggs). One can also see the change in the color of the solution due to the formation of Al(OH)3.

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