The equation 6KMnO4 + 4H2SO4 -> 3K2SO4 + 2Mn2(SO4)3 + 4H2O + 5O2

  1. Detailed information about the equation 6KMnO4 + 4H2SO4 -> 3K2SO4 + 2Mn2(SO4)3 + 4H2O + 5O2:
  • This is a chemical equation describing the reaction process between potassium permanganate (KMnO4) and sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4), manganese (III) sulfate (Mn2(SO4)3), water (H2O), and oxygen (O2).
  1. Reaction conditions:
  • This reaction requires high temperature and pressure to occur.
  1. Reaction process:
  • Potassium permanganate and sulfuric acid react to produce potassium sulfate, manganese (III) sulfate, water, and oxygen. In this process, KMnO4 is oxidized from oxidation state +7 (in KMnO4) to +3 (in Mn2(SO4)3), while the oxygen atom in H2SO4 is reduced from oxidation state +6 to +4 (in O2).
  1. Observed phenomena:
  • Potassium permanganate has a dark purple color, while the reaction products potassium sulfate and manganese (III) sulfate are colorless. Therefore, an observable phenomenon is that the purple color of the solution will disappear when the reaction occurs. In addition, oxygen gas will be released during this process.

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