The equation 6HNO3 + 3Sb2S3 -> 3Sb2O5 + 6NO + 6H2O

  1. Detailed information about the equation 6HNO3 + 3Sb2S3 -> 3Sb2O5 + 6NO + 6H2O:

This equation describes a reaction between nitric acid (HNO3) and antimony (III) sulfide (Sb2S3) to form antimony pentoxide (Sb2O5), nitric oxide (NO), and water (H2O).

  1. Reaction conditions:

This is a redox reaction, requiring an acidic environment to occur. Specific reaction conditions may vary depending on the temperature, pressure, and concentration of the reactants.

  1. Reaction process:

In this reaction, nitric acid (HNO3) reacts with antimony (III) sulfide (Sb2S3), oxidizing antimony from +3 to +5 state and reducing nitrate from +5 to +2 state. The result is the formation of antimony pentoxide (Sb2O5), nitric oxide (NO), and water (H2O).

  1. Occurring phenomena:

When the reaction occurs, boiling, smoking phenomena can be observed and there is a characteristic smell of nitric oxide gas. If the reaction is carried out under laboratory conditions, nitric oxide gas will escape and can be dangerous to the operator as this gas is very toxic when inhaled.

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