The equation 4KMnO4 + 8H2SO3 -> 4K2SO3 + 8MnSO4 + 8H2O

  1. Detailed information about the equation 4KMnO4 + 8H2SO3 -> 4K2SO3 + 8MnSO4 + 8H2O:
  • On the left side of the equation are the reactants including: KMnO4 (potassium permanganate) and H2SO3 (sulfurous acid III).
  • On the right side of the equation are the reaction products including: K2SO3 (potassium sulfite), MnSO4 (manganese sulfate II) and H2O (water).
  1. Reaction conditions:
  • The reaction occurs in an acidic environment.
  1. Reaction process:
  • This reaction is a redox process. In which, KMnO4 acts as a strong oxidizing agent, oxidizing H2SO3 from the oxidation state +4 of sulfur to +6, while KMnO4 itself is reduced from the oxidation state +7 of manganese to +2.
  1. Observable phenomenon:
  • When KMnO4 and H2SO3 react, water is formed and the color of the solution changes from the purple of potassium permanganate to the colorless of potassium sulfite and the light pink of manganese sulfate II.

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