The equation 4KMnO4 + 6H2O2 -> 4KOH + 4MnO2 + 4H2O + 6O2

  1. Detailed information about the equation 4KMnO4 + 6H2O2 -> 4KOH + 4MnO2 + 4H2O + 6O2:

This chemical equation describes the reaction process between potassium permanganate (KMnO4) and hydrogen peroxide (H2O2), the reaction products are potassium hydroxide (KOH), manganese dioxide (MnO2), water (H2O) and oxygen (O2).

  1. Reaction conditions:

This reaction usually occurs in an acidic or alkaline environment depending on the concentration of the two reactants.

  1. Reaction process:

Potassium permanganate is reduced to manganese dioxide while hydrogen peroxide is oxidized to oxygen. This is because KMnO4 has a strong oxidizing capacity while H2O2 has an antioxidant capacity.

  1. Phenomena occurring:

When the reaction occurs, it is manifested by the characteristic purple color of potassium permanganate gradually disappearing and being replaced by the brown color of manganese dioxide. In addition, oxygen is released in the form of gas, which can be identified by the appearance of gas bubbles.

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