The equation 4KMnO4 + 6H2O2 -> 4KOH + 4MnO2 + 3H2O + 5O2

  1. Detailed information about the equation 4KMnO4 + 6H2O2 -> 4KOH + 4MnO2 + 3H2O + 5O2:

The above equation describes the redox reaction between Potassium permanganate (KMnO4) and Hydrogen peroxide (H2O2) to form Potassium hydroxide (KOH), Manganese dioxide (MnO2), Water (H2O), and Oxygen (O2).

  1. Reaction condition:

For the reaction to occur, the presence of light is required. In addition, increasing the temperature also helps to speed up the reaction.

  1. Reaction process:

When KMnO4 and H2O2 come into contact with each other, KMnO4 is reduced from the oxidation state +7 to +4 to form MnO2, while H2O2 is oxidized from the oxidation state -1 up to 0 to form O2.

  1. Observable phenomena:

When the reaction occurs, we can observe the color change from the purple of KMnO4 to the brown of MnO2. In addition, we will also see Oxygen gas being released in the form of bubbles.

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