The equation 4KMnO4 + 12H2SO4 -> 4K2SO4 + 12MnSO4 + 8H2O + 5O2

Detailed information about the equation 4KMnO₄ + 12H₂SO₄ -> 4K₂SO₄ + 12MnSO₄ + 8H₂O + 5O₂:

• This equation describes the redox reaction between potassium permanganate (KMnO₄) and sulfuric acid (H₂SO₄) to form potassium sulfate (K₂SO₄), manganese sulfate (MnSO₄), water (H₂O), and oxygen (O₂).

Reaction conditions:

• The reaction occurs in a strong acidic environment.

Reaction Process:

• In this reaction, KMnO₄ is oxidized to K₂SO₄ and MnO₂, then MnO₂ is reduced to MnSO₄. H₂SO₄ plays the role of a reducing agent, helping to oxidize KMnO₄ to MnO₂, and then reduce it to MnSO₄.

Phenomena occur:

• When the reaction occurs, the purple color of KMnO₄ gradually fades, turning into the pale pink color of MnSO₄. At the same time, oxygen gas is released, which can be seen with the naked eye or through the phenomenon of brighter burning candles.