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- Detailed information about the equation 4KMnO4 + 12H2SO3 -> 4K2SO3 + 12MnSO4 + 6H2O:
- The left side of the equation represents the reactants which includes: KMnO4 (Potassium permanganate) and H2SO3 (Sulfurous acid).
- The right side of the equation represents the products after the reaction, including: K2SO3 (Potassium sulfite), MnSO4 (Manganese (II) sulfate) and H2O (water).
- The number of moles of the reactants and products is represented before the names of the substances.
- Reaction conditions:
- The conditions for this reaction typically occur at room temperature.
- H2SO3 needs to be in a solution form to easily react with KMnO4.
- Reaction Process:
- This process is a redox reaction. KMnO4 has the capability to oxidize H2SO3 into K2SO3, during this process KMnO4 is also reduced to MnSO4.
- Chemical stoichiometry shows that this reaction requires 4 moles of KMnO4 to react with 12 moles of H2SO3 to produce 4 moles of K2SO3, 12 moles of MnSO4 and 6 moles of H2O.
- Observed phenomena:
- When KMnO4 reacts with H2SO3, the solution will change color from the purple of KMnO4 to a light pink or colorless. This is a sign that KMnO4 has been reduced.
- Simultaneously, the product MnSO4 will make the solution cloudy.