The equation 4HNO3 + Cu3S2 -> 2NO2 + 2H2O + 2Cu(NO3)2 + 2S

  1. Detailed information about the equation 4HNO3 + Cu3S2 -> 2NO2 + 2H2O + 2Cu(NO3)2 + 2S:
  • This equation describes the reaction process between nitric acid (HNO3) and copper sulfide (Cu3S2). The result of the reaction is nitrogen dioxide (NO2), water (H2O), copper (II) nitrate (Cu(NO3)2), and sulfur (S).
  1. Reaction Conditions:
  • The general conditions for the reaction to occur are sufficient temperature, pressure, and contact between the reactants.
  1. Reaction Process:
  • During the reaction process, copper sulfide will react with nitric acid to produce copper (II) nitrate, sulfur, nitrogen dioxide, and water.
  1. Phenomenon Occurrence:
  • When the reaction occurs, we can observe changes in the color and volume of the reacting substances. Some substances will disappear, and some new substances will appear.
  • Specifically, nitric acid is light yellow, and copper sulfide is black. When the reaction occurs, the color of the mixture changes. Copper (II) nitrate is blue, nitrogen dioxide is red-orange, and sulfur is yellow.

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