The equation 2KMnO4 + 5H2SO3 -> 2K2SO3 + 2MnSO4 + 5H2O + 2SO2

  1. Detailed information about the chemical equation:
    The above chemical equation describes the redox reaction between potassium permanganate (KMnO4) and sulfurous acid III (H2SO3), resulting in potassium sulfite (K2SO3), manganese sulfate (MnSO4), water (H2O), and sulfur dioxide (SO2).

  2. Reaction conditions:
    The reaction occurs in an acidic environment.

  3. Reaction process:

    • Potassium permanganate (KMnO4) is reduced to manganese sulfate (MnSO4).
    • Sulfurous acid III (H2SO3) is oxidized to sulfur dioxide (SO2) and water (H2O).
    • Potassium (K) in potassium permanganate (KMnO4) combines with sulfite (SO3) from sulfurous acid III (H2SO3) to form potassium sulfite (K2SO3).

  4. Occurrences:
    During the reaction process, the purple color of the potassium permanganate (KMnO4) solution gradually disappears until it is completely colorless. Simultaneously, sulfur dioxide (SO2) gas is released.

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