The equation 2KMnO4 + 3H2SO4 -> K2SO4 + 2MnSO4 + 3H2O + 5O2

  1. Detailed information about the equation 2KMnO4 + 3H2SO4 -> K2SO4 + 2MnSO4 + 3H2O + 5O2:
    The equation indicates the redox process between potassium permanganate (KMnO4) and sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4), manganese sulfate (MnSO4), water (H2O), and oxygen (O2).

  2. Reaction conditions:
    This reaction typically occurs under normal temperature conditions. However, the temperature can be increased to accelerate the reaction rate.

  3. Reaction process:
    In this reaction, potassium permanganate (KMnO4) and sulfuric acid (H2SO4) interact with each other, during which KMnO4 is reduced to MnSO4 and H2SO4 is oxidized to K2SO4 and O2.

  4. Phenomena occur:
    When the reaction occurs, the initial purple liquid from KMnO4 disappears and is replaced by the appearance of the white solid of K2SO4 and the light pink liquid of MnSO4. Along with this is the release of oxygen gas (O2).

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