This equation describes the redox reaction between potassium (K) and copper(II) oxide (CuO). In the reaction, K is oxidised (loses e) from an oxidation state of 0 to +1, while CuO is reduced from an oxidation state of +2 to 0, releasing oxygen to form K2O (potassium oxide) and Cu (pure copper).
- Reaction conditions
This reaction requires high temperatures to occur. It is usually carried out in a furnace at high temperatures.
- Reaction process
When potassium and copper(II) oxide are placed in a furnace at high temperatures, potassium gives its electron to the Cu2+ ion in copper(II) oxide, releasing oxygen and forming potassium oxide and pure copper.
- Phenomena occurring
During the reaction process, heat and light are released. The products of the reaction are potassium oxide, a white solid, and copper, a metal with a characteristic red color.