The equation 10HNO3 + 3Cu2S -> 3Cu(NO3)2 + 5H2O + 5NO + 3SO2

  1. Detailed information on the equation 10HNO3 + 3Cu2S -> 3Cu(NO3)2 + 5H2O + 5NO + 3SO2

The chemical equation above describes the reaction between nitric acid (HNO3) and copper sulfide (Cu2S). The result of this reaction is the formation of copper(II) nitrate (Cu(NO3)2), water (H2O), nitric oxide (NO) and sulfur dioxide (SO2).

  1. Reaction Conditions

For the reaction to occur, the presence of high temperature and suitable pressure are needed. Simultaneously, the nitric acid needs to be in high concentration to ensure the reaction takes place effectively.

  1. Reaction Process

During the reaction process, nitric acid will act upon copper sulfide, breaking the chemical bonds and producing the reaction products. When the copper atoms in copper sulfide come into contact with nitric acid, they will be oxidized and form copper(II) nitrate. In this process, sulfur is also oxidized to sulfur dioxide.

  1. Phenomena Occurring

When the reaction occurs, you can observe changes in color and temperature. The black-colored copper sulfide is transformed into blue-colored copper(II) nitrate. Simultaneously, the reaction also releases heat, causing the reaction mixture to warm up.

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