The chemical equation 6HNO3 + 2CuO -> 4NO2 + 2H2O + 2Cu(NO3)2

  1. Detailed information about the chemical equation 6HNO3 + 2CuO -> 4NO2 + 2H2O + 2Cu(NO3)2:

    • The above equation describes the reaction between nitric acid (HNO3) and copper(II) oxide (CuO), resulting in nitrogen dioxide (NO2), water (H2O), and copper(II) nitrate (Cu(NO3)2).
    • HNO3, CuO, NO2, H2O, and Cu(NO3)2 are respectively the reactants and products of the reaction.
    • The numbers 6, 2, 4, 2, 2 are the stoichiometric coefficients of the reactants and products in the reaction.

  2. Reaction conditions:

    • This reaction usually occurs at room temperature. However, increasing the temperature can speed up the reaction.

  3. Reaction process:

    • Initially, nitric acid and copper(II) oxide coexist in the reaction environment.
    • When these two substances come into contact with each other, nitric acid will act on copper(II) oxide, causing it to decompose into nitrogen dioxide, water, and copper(II) nitrate.

  4. Occurring phenomena:

    • During the reaction process, you will see a quantity of orange gas (nitrogen dioxide) being released.
    • At the same time, the original chemicals (nitric acid and copper(II) oxide) gradually disappear, replaced by the formation of copper(II) nitrate and water.

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