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Detailed information about the equation 2KClO3 -> 2KCl + 3O2 -> :
This chemical equation describes the decomposition reaction of potassium chlorate (KClO3) into potassium chloride (KCl) and oxygen gas (O2). In this reaction, 2 moles of KClO3 decompose to produce 2 moles of KCl and 3 moles of O2. -
Reaction conditions:
This reaction requires heat to occur, usually at high temperatures. When heated, KClO3 will decompose. -
Reaction process:
As the temperature increases, the KClO3 molecules receive more energy, increasing the collision rate between molecules and the KClO3 molecules begin to decompose into KCl and O2. -
Phenomena occurring:
When the temperature is high enough, KClO3 begins to decompose and produces oxygen gas. The oxygen gas will escape in the form of bubbles if the reaction occurs in a solution or in the form of gas if the reaction occurs in air. Simultaneously, solid KCl is also formed.