The equation 4Pb3O4 -> 12PbO + 3O2

  1. Detailed information about the equation 4Pb3O4 -> 12PbO + 3O2 -> :

    • The equation above describes the decomposition process of lead (II, IV) oxide (Pb3O4) forming lead (II) oxide (PbO) and oxygen (O2).

  2. Reaction conditions:

    • This decomposition reaction occurs when the temperature rises.

  3. Reaction process:

    • In the reaction process, 4 mol of lead (II, IV) oxide (Pb3O4) decompose to form 12 mol of lead (II) oxide (PbO) and 3 mol of oxygen (O2).

  4. Phenomena occurring:

    • As the temperature rises, lead (II, IV) oxide will change from red to yellow due to the formation of lead (II) oxide.
    • If the reaction takes place in a sealed container, you will see the pressure in the container increase due to the formation of oxygen gas.

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