The equation 2K2Cr2O7 -> 2Cr2O3 + 4K2CrO4 + 3O2

Detailed information about the equation 2K₂Cr₂O₇ -> 2Cr₂O₃ + 4K₂CrO₄ + 3O₂ -> : This is a redox equation, in which K₂Cr₂O₇ (potassium dichromate) is oxidized into Cr₂O₃ (chromium(III) oxide) and K₂CrO₄ (potassium chromate), along with the release of O₂ (oxygen gas).

Reaction conditions: The condition for this reaction to occur is high temperature. K₂Cr₂O₇ has a strong oxidizing ability, so it can generate oxygen gas when the temperature rises.

Reaction process: As the temperature increases, K₂Cr₂O₇ decomposes into Cr₂O₃, K₂CrO₄ and oxygen gas. K₂Cr₂O₇ is a strong oxidizing agent, so it can generate oxygen gas.

Observed phenomena: During the reaction, one can observe the release of oxygen gas. Also, if the reaction is carried out in a visible instrument, one can see the color change from the orange of K₂Cr₂O₇ to the green of Cr₂O₃ and the yellow of K₂CrO₄.