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Detailed information about the chemical equation 6HNO3 + 2CuO -> 4NO2 + 2H2O + 2Cu(NO3)2:
- The above equation describes the reaction between nitric acid (HNO3) and copper(II) oxide (CuO), resulting in nitrogen dioxide (NO2), water (H2O), and copper(II) nitrate (Cu(NO3)2).
- HNO3, CuO, NO2, H2O, and Cu(NO3)2 are respectively the reactants and products of the reaction.
- The numbers 6, 2, 4, 2, 2 are the stoichiometric coefficients of the reactants and products in the reaction.
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Reaction conditions:
- This reaction usually occurs at room temperature. However, increasing the temperature can speed up the reaction.
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Reaction process:
- Initially, nitric acid and copper(II) oxide coexist in the reaction environment.
- When these two substances come into contact with each other, nitric acid will act on copper(II) oxide, causing it to decompose into nitrogen dioxide, water, and copper(II) nitrate.
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Occurring phenomena:
- During the reaction process, you will see a quantity of orange gas (nitrogen dioxide) being released.
- At the same time, the original chemicals (nitric acid and copper(II) oxide) gradually disappear, replaced by the formation of copper(II) nitrate and water.