The equation 4HNO3 + CuSe -> 2NO2 + 2H2O + Cu(NO3)2 + Se

  1. Detailed information about the equation 4HNO3 + CuSe -> 2NO2 + 2H2O + Cu(NO3)2 + Se

The equation shows the reaction between nitric acid (HNO3) and copper(II) selenide (CuSe) to produce nitrogen dioxide (NO2), water (H2O), copper(II) nitrate (Cu(NO3)2), and selenium (Se).

  1. Reaction conditions

This is a redox reaction that occurs at room temperature between nitric acid and copper(II) selenide.

  1. Reaction process

The reaction process occurs when nitric acid reacts with copper(II) selenide, producing nitrogen dioxide, water, copper(II) nitrate, and selenium. In this process, copper(II) selenide and nitric acid are oxidized, while copper(II) nitrate and selenium are reduced.

  1. Phenomena occurring

During the reaction process, when the two substances are mixed together, the color of the mixture will change. Specifically, the appearance of nitrogen dioxide will create a reddish-brown color, while selenium creates a red color. Additionally, there may be gas release during the reaction process.

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