The equation 8HNO3 + 2Cu2S -> 2Cu(NO3)2 + 4H2O + 4NO + 2SO2

  1. Detailed information about the equation 8HNO3 + 2Cu2S -> 2Cu(NO3)2 + 4H2O + 4NO + 2SO2

    • The above equation represents the reaction process between nitric acid (HNO3) and copper sulfide (Cu2S). The result of the reaction is the production of copper(II) nitrate (Cu(NO3)2), water (H2O), nitrogen monoxide (NO), and sulfur dioxide (SO2).

  2. Reaction Conditions

    • This reaction takes place at room temperature.

  3. Reaction Process

    • During the reaction process, nitric acid (HNO3) acts on copper sulfide (Cu2S) to produce copper(II) nitrate (Cu(NO3)2), water (H2O), nitrogen monoxide (NO), and sulfur dioxide (SO2).

  4. Phenomena that occur

    • When nitric acid (HNO3) reacts with copper sulfide (Cu2S), it produces a blue solid, copper(II) nitrate (Cu(NO3)2).
    • At the same time, nitrogen monoxide (NO) gas is released, giving off a quite distinct smell.
    • Water vapor (H2O) and sulfur dioxide (SO2) are also released in the form of steam. Sulfur dioxide (SO2) has a pungent smell and can irritate the respiratory tract.

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