The equation 6HNO3 + 3CuS -> 3Cu(NO3)2 + 6H2O + 3NO

  1. Detailed information about the equation 6HNO3 + 3CuS -> 3Cu(NO3)2 + 6H2O + 3NO:

    • This equation describes the oxidation process of copper sulfide (CuS) by nitric acid (HNO3) to form copper (II) nitrate (Cu(NO3)2), water (H2O), and nitric oxide (NO).
    • In this process, copper sulfide is oxidized from +1 to +2, and nitrogen in nitric acid is reduced from +5 to +2.

  2. Reaction conditions:

    • This reaction requires sufficient temperature to occur, usually high temperature is used.
    • Adequate reaction products must be available.

  3. Reaction process:

    • Firstly, copper sulfide reacts with nitric acid to form copper (II) nitrate, water, and nitric oxide.
    • In this process, copper sulfide is oxidized from +1 to +2, and nitrogen in nitric acid is reduced from +5 to +2.

  4. Phenomenon occurrence:

    • When the reaction takes place, you will see a characteristic phenomenon is the color change of the solution from green to deep blue, while generating brown nitrogen oxide gas.

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