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- Detailed information about the equation 12HNO3 + 3CuS -> 3Cu(NO3)2 + 6H2O + 6NO + 3SO2:
- This equation describes the reaction between nitric acid (HNO3) and copper sulfide (CuS).
- In this reaction, 12 mol of HNO3 reacts with 3 mol of CuS to produce 3 mol of Cu(NO3)2, 6 mol of H2O, 6 mol of NO and 3 mol of SO2.
- The products of the reaction are copper(II) nitrate (Cu(NO3)2), water (H2O), nitric oxide (NO) and sulfur dioxide (SO2).
- Reaction conditions:
- This reaction requires concentrated nitric acid and high temperatures to occur.
- The reaction typically occurs under normal pressure.
- Reaction process:
- Initially, nitric acid (HNO3) reacts with copper sulfide (CuS) to produce copper(II) nitrate (Cu(NO3)2) and sulfuric acid (H2SO4).
- The sulfuric acid then continues to react with nitric acid (HNO3) to produce water (H2O), nitric oxide (NO) and sulfur dioxide (SO2).
- Phenomena occur:
- When the reaction occurs, there is a color change from the black of CuS to the blue of Cu(NO3)2.
- The volume of the solution decreases significantly.
- Gases NO and SO2 are released with a distinctive smell.
- If conducted in sealed conditions, an increase in pressure within the system can be observed.