The chemical equation KMnO4 + H2O2 -> K2MnO4 + H2O + O2

1. The above chemical equation describes the reaction between potassium permanganate (KMnO₄) and hydrogen peroxide (H₂O₂) to form potassium manganate (K₂MnO₄), water (H₂O), and oxygen (O₂).

2. Reaction conditions: This is a redox reaction, in which the KMnO₄ of potassium permanganate is reduced to K₂MnO₄ and the H₂O₂ of hydrogen peroxide is oxidized to water and oxygen. The reaction can occur in both acidic or alkaline environments, but it is usually conducted in an alkaline environment to produce manganate.

3. Reaction process: In the reaction process, H₂O₂ acts as a reducing agent; it will convert KMnO₄ into K₂MnO₄ and water.

4. Phenomenon that occur: The color of the solution will change. Initially, the potassium permanganate solution is purple, but after the reaction, it will turn into the blue color of potassium manganate. In addition, oxygen is released as a gas during the reaction, which can be observed by the appearance of gas bubbles.

Keep in mind that the above equation is not balanced. The balanced equation would be: 2KMnO₄ + 3H₂O₂ -> 2K₂MnO₄ + 2H₂O + 3O₂.