The equation 8KMnO4 + 5H2C2O4 -> 8K2C2O4 + 2Mn2(SO4)3 + 10H2O + 2CO2

Detailed information about the equation 8KMnO₄ + 5H₂C₂O₄ -> 8K₂C₂O₄ + 2Mn₂(SO₄)₃ + 10H₂O + 2CO₂:

The above chemical equation illustrates the redox reaction between potassium permanganate (KMnO₄) and oxalic acid (H₂C₂O₄).
In this reaction, KMnO₄ is a strong oxidizing agent, which oxidizes H₂C₂O₄ into K₂C₂O₄ (potassium oxalate) and CO₂ (carbon dioxide gas).
The manganese atom in KMnO₄ is reduced from the oxidation state of +7 to the oxidation state of +3, forming Mn₂(SO₄)₃ (manganese (III) sulfate).

Reaction conditions:

This reaction usually occurs in an acidic environment.

Reaction process:

First, KMnO₄ and H₂C₂O₄ must be mixed in an acid solution to create a suitable environment for the reaction.
KMnO₄ will oxidize H₂C₂O₄, producing K₂C₂O₄ and CO₂.
The manganese atom in KMnO₄ is reduced into Mn₂(SO₄)₃ and water.
The overall reaction process produces K₂C₂O₄, Mn₂(SO₄)₃, H₂O and CO₂.

Phenomena occurred:

First, the purple solution of KMnO₄ will gradually fade as KMnO₄ is reduced.
Next, the production of CO₂ gas can be observed as bubbles rising from the solution.
Finally, a solution containing K₂C₂O₄ and Mn₂(SO₄)₃ is produced.

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