The equation is 5KMnO4 + 8H2C2O4 -> 5K2C2O4 + 5MnSO4 + 8H2O.

1. Detailed information about the equation 5KMnO₄ + 8H₂C₂O₄ -> 5K₂C₂O₄ + 5MnSO₄ + 8H₂O

The above equation describes the reaction process between potassium permanganate (KMnO₄) and oxalic acid (H₂C₂O₄) at a ratio of 5:8 to form potassium oxalate (K₂C₂O₄), manganese sulfate (MnSO₄) and water (H₂O).

2. Reaction conditions

This reaction occurs in an acidic environment.

3. Reaction process

When KMnO₄ and H₂C₂O₄ meet in an acidic environment, KMnO₄ is reduced to MnSO₄, while H₂C₂O₄ is oxidized to K₂C₂O₄ and water. This is a redox reaction.

4. Occurring phenomena

During the reaction process, the solution will change from the purple color of KMnO₄ to the colorless of MnSO₄.