The equation 4KMnO4 + 9H2SO4 -> 4K2SO4 + 4MnSO4 + 9H2O + 5SO2 + 8O2

  1. Detailed information about the equation 4KMnO4 + 9H2SO4 -> 4K2SO4 + 4MnSO4 + 9H2O + 5SO2 + 8O2

    • This is a chemical reaction that occurs between potassium permanganate (KMnO4) and sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4), manganese sulfate (MnSO4), water (H2O), sulfur dioxide (SO2) and oxygen (O2).

  2. Reaction conditions

    • This is a redox reaction that occurs in an acidic environment, so the presence of H2SO4 is required.
    • The conditions for temperature and pressure are not too strict, the reaction can occur stably under normal temperature and pressure conditions.

  3. Reaction process

    • The redox process occurs when manganese in KMnO4 is oxidized from the +7 oxidation state down to +2, while the sulfur in H2SO4 is reduced from the +6 oxidation state down to +4.

  4. Phenomena occurred

    • The characteristic purple color of KMnO4 will disappear, while SO2 will emit white smoke.
    • The observable reaction phenomenon is that the solution gradually changes from purple to colorless (due to the oxidation of KMnO4) and white SO2 gas appears.

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