The equation 2KMnO4 + 4H2C2O4 -> K2C2O4 + 2MnSO4 + 4H2O

Detailed Information about the Equation: The equation describes the reaction between potassium permanganate (KMnO₄) and oxalic acid (H₂C₂O₄) to produce potassium oxalate (K₂C₂O₄), manganese sulfate (MnSO₄), and water (H₂O). This is a redox reaction in which KMnO₄ acts as an oxidizing agent and H₂C₂O₄ acts as a reducing agent.

Reaction Conditions: This reaction typically occurs in an acidic environment. In an acidic environment, KMnO₄ is reduced to MnSO₄, while H₂C₂O₄ is oxidized to K₂C₂O₄ and H₂O.

Reaction Process: The reaction process proceeds as follows:

2KMnO₄ + 4H₂C₂O₄ -> K₂C₂O₄ + 2MnSO₄ + 4H₂O

Wherein:

• 2 molecules of KMnO₄ react with 4 molecules of H₂C₂O₄ to produce 1 molecule of K₂C₂O₄, 2 molecules of MnSO₄, and 4 molecules of H₂O.

Observed Phenomenon: When the reaction occurs, the purple solution of potassium permanganate gradually disappears, forming a pale pink solution of manganese sulfate. This phenomenon is commonly observed in this experiment.