The equation 2KMnO4 + 3H2SO3 -> K2SO4 + 2MnSO4 + 3H2O

Detailed information about the equation:
The equation indicates the reaction between potassium permanganate (KMnO₄) and sulfurous acid (H₂SO₃) to produce potassium sulfate (K₂SO₄), manganese sulfate (MnSO₄), and water (H₂O). This is a type of chemical reaction known as a redox reaction. Herein, the manganese in KMnO₄ is reduced from an oxidation state of +7 to +2, while the sulfur in H₂SO₃ is oxidized from an oxidation state of +4 to +6.

Reaction conditions:
For the reaction to occur effectively, the necessary condition is an acidic environment. This is because KMnO₄ has its strongest reducing ability in acidic conditions. H₂SO₃ creates the necessary acidic environment for the reaction.

Reaction process:
When the two substances KMnO₄ and H₂SO₃ meet in an acidic environment, KMnO₄ is reduced to MnSO₄, while H₂SO₃ is oxidized to K₂SO₄. The reaction continues until one of the reactants is exhausted.

Occurring phenomena:
When the reaction occurs, the characteristic purple color of KMnO₄ gradually disappears, replaced by the pale pink color of MnSO₄. Simultaneously, gas is generated in the solution, indicating the formation of H₂O.