The equation 2KMnO4 + 3H2O2 -> 2KOH + 2MnO2 + 2H2O + O2

  1. Detailed information about the equation:

    • The chemical equation above describes the chemical reaction between potassium permanganate (KMnO4) and hydrogen peroxide (H2O2), resulting in potassium hydroxide (KOH), manganese dioxide (MnO2), water (H2O) and oxygen (O2).

  2. Reaction conditions:

    • This reaction takes place under reducing conditions (KMnO4 is reduced to MnO2).
    • The presence of a catalyst is necessary to accelerate the reaction.

  3. Reaction process:

    • In this process, KMnO4 acts as a strong oxidizing agent, reducing hydrogen peroxide (H2O2) to water (H2O) and oxygen (O2).
    • After the reaction, KMnO4 is self-reduced to MnO2.

  4. Phenomena observed:

    • As the reaction begins, the purple solution of potassium permanganate gradually fades and turns brown due to the formation of manganese dioxide.
    • The release of oxygen gas during the reaction can be observed.

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