The equation 2KMnO4 + 3H2C2O4 -> K2C2O4 + 2MnSO4 + 3H2O + 2CO2

  1. Detailed information about the equation 2KMnO4 + 3H2C2O4 -> K2C2O4 + 2MnSO4 + 3H2O + 2CO2:

    • Based on the relationship between the amount of reactants and the amount of product, this equation corresponds to 2 moles of KMnO4 (Potassium permanganate) reacting with 3 moles of H2C2O4 (Oxalic acid) to produce 1 mole of K2C2O4 (Potassium oxalate), 2 moles of MnSO4 (Manganese(II) sulfate), 3 moles of H2O (Water) and 2 moles of CO2 (Carbon dioxide gas).
    • This equation also shows that this chemical reaction is a redox reaction in which KMnO4 acts as an oxidizing agent (being reduced) and H2C2O4 acts as a reducing agent (being oxidized).

  2. Reaction Conditions:

    • General conditions: The reaction occurs at room temperature and standard pressure.
    • Specific conditions: The reaction proceeds well in acidic environment (like sulfuric acid H2SO4 environment).

  3. Reaction Process:

    • In the reaction process, KMnO4 is reduced to MnSO4, while H2C2O4 is oxidized to CO2 and water.

  4. Phenomenon Occurring:

    • The purple-red solution of KMnO4 gradually disappears and creates an undefined colored solution, indicating the presence of colorless MnSO4.
    • Bubbles of CO2 gas are released.
    • K2C2O4 formed may precipitate if the concentration in the solution is high enough.

Leave a Comment