The equation Ba(OH)2 + H2SO4 -> BaSO4 + 2H2O

  1. Detailed information about the equation Ba(OH)2 + H2SO4 -> BaSO4 + 2H2O
  • Ba(OH)2 is Barium hydroxide, a white solid, soluble in water, colorless, odorless, and strongly alkaline.
  • H2SO4 is sulfuric acid, a colorless liquid, with a strong smell, flammable, and strongly acidic.
  • BaSO4 is Barium sulfate, a white solid, insoluble in water, colorless, odorless, and non-toxic.
  • 2H2O is water, a colorless, odorless, tasteless liquid, non-flammable, and non-toxic.
  1. Reaction conditions

This reaction occurs at room temperature and standard pressure. Barium hydroxide (Ba(OH)2) and sulfuric acid (H2SO4) need to come into contact with each other to start the reaction.

  1. Reaction process

Ba(OH)2 and H2SO4 react with each other to produce BaSO4 and 2H2O. The strong base Ba(OH)2 will swallow the H+ ion of the strong acid H2SO4 to create water (H2O). Ba2+ will combine with SO4 (2-) to form a precipitate of BaSO4.

  1. Occurring phenomenon

When barium hydroxide reacts with sulfuric acid, a white precipitate of barium sulfate and water is formed.

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