The chemical equation Al2O3 + 6HCl -> 2AlCl3 + 3H2O

  1. Detailed information about the equation Al2O3 + 6HCl -> 2AlCl3 + 3H2O

    • The equation above describes the chemical reaction between aluminum oxide (Al2O3) and hydrochloric acid (HCl) to form aluminum chloride (AlCl3) and water (H2O).
    • According to the law of conservation of mass, each 102 grams of aluminum oxide (corresponding to 1 mol Al2O3) will react with 219 grams of HCl (corresponding to 6 mol HCl) to yield 267.5 grams of aluminum chloride (corresponding to 2 mol AlCl3) and 54 grams of water (corresponding to 3 mol H2O).

  2. Reaction conditions

    • The condition for the reaction to occur is to have enough HCl to react with Al2O3.
    • This reaction takes place at high temperatures.

  3. Reaction process

    • The reaction process begins when Al2O3 comes into contact with HCl. At this point, Al2O3 will split into 2 Al ions and 3 O ions, while HCl will split into H ions and Cl ions.
    • Next, the 2 Al ions will combine with the 6 Cl ions to form 2 mol AlCl3, while the 6 H ions will combine with the 3 O ions to form 3 mol H2O.

  4. Phenomena occurring

    • The phenomena that occur during the reaction include: boiling, evaporation of the solution, gas formation (if the reaction is in a closed condition) and reduction in the volume of the solution.

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