The equation ZnSO4 + KOH -> Zn(OH)2 + K2SO4

  1. Detailed information about the equation ZnSO4 + KOH -> Zn(OH)2 + K2SO4:

The above equation represents a neutralization reaction between the sulfate salt of the transition metal zinc (ZnSO4) and the strong base potassium hydroxide (KOH). The result of this reaction is the formation of zinc hydroxide (Zn(OH)2), a white precipitate, and potassium sulfate (K2SO4).

  1. Reaction conditions:

This reaction takes place at room temperature and standard pressure. KOH needs to be dissolved in water to create a solution before combining with ZnSO4.

  1. Reaction process:

When ZnSO4 combines with KOH, it forms Zn(OH)2 and K2SO4. In this process, the zinc ion (Zn2+) from ZnSO4 combines with the hydroxide ion (OH-) from KOH to form zinc hydroxide. At the same time, the potassium ion (K+) from KOH combines with the sulfate ion (SO4^2-) from ZnSO4 to form potassium sulfate.

  1. Phenomena occurring:

When the two reactants combine, a white precipitate of zinc hydroxide and a solution of potassium sulfate are formed. If the reaction takes place in a water glass, you will see the white precipitate forming and settling at the bottom of the glass.

Leave a Comment