The equation Fe2O3 + 3H2SO4 -> Fe2(SO4)3 + 3H2O

The chemical equation above describes the reaction between Iron(III) oxide (Fe₂O₃) and sulfuric acid (H₂SO₄) to produce Iron(III) sulfate (Fe₂(SO₄)₃) and water (H₂O). This equation is balanced, with the reaction ratio being 1 mol Fe₂O₃ reacts with 3 mol H₂SO₄ to produce 1 mol Fe₂(SO₄)₃ and 3 mol H₂O.

Reaction conditions:
The conditions for this reaction require sulfuric acid to be at a high concentration and the reaction to take place under high temperature.

Reaction process:
Iron(III) oxide reacts with sulfuric acid to form Iron(III) sulfate and water. This process occurs under high temperature conditions and high concentration of sulfuric acid.

Phenomena occurring:
When the reaction takes place, we can observe the phenomenon of the reddish-brown solid of Iron(III) oxide gradually disappearing, replaced by the greenish product of Iron(III) sulfate solution. At the same time, there is a change in heat, indicating that the reaction is exothermic.