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- Detailed information about the equation CuS + 2H2SO4 -> CuSO4 + 2H2O + 2SO2
- The above equation is a chemical reaction that occurs between copper sulfide (CuS) and sulfuric acid (H2SO4), resulting in copper sulfate (CuSO4), water (H2O), and sulfur dioxide gas (SO2).
- Reaction conditions
- The reaction takes place at high temperatures and in a strong acid environment.
- Reaction process
- The reaction begins with copper sulfide (CuS) reacting with sulfuric acid (H2SO4) under the influence of heat to produce copper sulfate (CuSO4), water (H2O), and sulfur dioxide gas (SO2).
- During this process, Cu2+ cations from CuS move into the solution, forming copper sulfate salt.
- At the same time, SO42- anions from H2SO4 move into the solution, forming copper sulfate salt and dissolving in water to form a CuSO4 solution.
- Occurring phenomena
- During the reaction, the black solid of copper sulfide (CuS) gradually disappears.
- The amount of sulfuric acid (H2SO4) solution gradually decreases.
- The appearance of the blue solid of copper sulfate (CuSO4) and the characteristic-smelling sulfur dioxide gas (SO2) escaping is observed.