The equation CuCl2 + KOH -> Cu(OH)2 + 2KCl

  1. Detailed information about the equation CuCl2 + KOH -> Cu(OH)2 + 2KCl:
    This chemical equation describes the reaction process between copper chloride (CuCl2) and potassium hydroxide (KOH), resulting in copper hydroxide (Cu(OH)2) and potassium chloride (KCl).

  2. Reaction conditions:
    This reaction takes place at room temperature and standard pressure.

  3. Reaction process:
    When copper chloride and potassium hydroxide come into contact with each other, they form copper hydroxide, a blue precipitate, and potassium chloride, a white solid, resulting in a blue solution.

  4. Phenomenon occurs:
    When copper chloride (CuCl2) reacts with potassium hydroxide (KOH), a precipitation phenomenon occurs. The result of the reaction is the formation of copper hydroxide (Cu(OH)2), a blue precipitate, and potassium chloride (KCl), a white solid.

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