The equation Fe + 6CuSO4 -> 2Fe2(SO4)3 + 6Cu

  1. Detailed information about the equation:
    The above equation describes the reaction between iron (Fe) and copper(II) sulfate (CuSO4) to form iron(III) sulfate (Fe2(SO4)3) and copper (Cu). This is a redox reaction, in which iron is oxidized from an oxidation state of +2 to +3, while copper is reduced from an oxidation state of +2 to 0.

  2. Reaction conditions:
    This reaction requires the presence of an acidic environment, typically sulfuric acid, to facilitate the reaction process.

  3. Reaction process:
    Iron reacts with copper(II) sulfate solution to form iron(III) sulfate and free copper. CuSO4 is reduced to Cu, while Fe is oxidized to Fe2(SO4)3.

  4. Phenomena occurring:
    When the reaction occurs, the color of the solution changes from sky blue (due to CuSO4) to reddish brown (due to Fe2(SO4)3), and reddish-brown copper particles appear.

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