The equation Fe + 4CuSO4 -> 2Fe2(SO4)3 + 4Cu

Detailed information about the reaction Fe + 4CuSO₄ -> 2Fe₂(SO₄)₃ + 4Cu
The above equation describes the chemical reaction between iron (Fe) and copper sulfate (CuSO₄) to form iron (III) sulfate (Fe₂(SO₄)₃) and copper (Cu). This reaction indicates that iron has a stronger reducing property than copper, leading to the reduction of Cu₂+ in copper sulfate solution to form copper metal, and simultaneously being oxidized to Fe₃+, forming iron (III) sulfate.

Reaction conditions
This reaction occurs under normal conditions of temperature and pressure. Iron needs to be in direct contact with the copper sulfate solution.

Reaction process
When iron comes into contact with copper sulfate solution, the Fe₂+ ions of iron will be oxidized to Fe₃+ and simultaneously reduce the Cu₂+ ions of copper sulfate to copper metal.

Phenomena occurring
When the reaction occurs, brownish-red copper particles will appear on the surface of the iron. The initially blue copper sulfate solution gradually turns murky brown due to the formation of iron (III) sulfate.