The equation is 2B + 3H2S -> B2S3 + 3H2.

Detailed information about the reaction 2B + 3H₂S -> B₂S₃ + 3H₂:

• Reactants: Boron (B) and Hydrogen Sulfide (H₂S)
• Products: Boron trisulfide (B₂S₃) and Hydrogen (H₂)
• This equation represents the reaction between boron and hydrogen sulfide to form boron trisulfide and hydrogen.

Reaction conditions:

• The specific conditions for this reaction may vary based on factors such as temperature, pressure, and the presence of a catalyst.
• However, in general, the reaction between boron and hydrogen sulfide usually requires high temperatures.

Reaction process:

• Boron reacts with hydrogen sulfide to produce boron trisulfide and hydrogen.
• This reaction typically occurs in a sealed container and may require increased temperature to provide enough activation energy for the reaction.

Phenomena occurring:

• During the reaction, boron in powder form will be consumed, forming a new solid substance, boron trisulfide.
• Hydrogen sulfide will also be consumed, while the volume of hydrogen gas increases.
• Another observable phenomenon is the increase in system temperature as this reaction is exothermic.