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- Detailed information on the chemical equation: 2Tl2O3 + 6NaOH -> 2Na3TlO3 + 3H2O
- On the left side (reactants): 2 moles of Tl2O3 (Thallium(III) oxide) react with 6 moles of NaOH (Sodium hydroxide)
- On the right side (products): 2 moles of Na3TlO3 (Sodium thallate(III)) and 3 moles of H2O (Water)
- Reaction conditions
- This reaction needs to be carried out at high temperatures to promote the reaction.
- Reaction process
- Thallium(III) oxide reacts with sodium hydroxide to form sodium thallate(III) and water.
- Thallium(III) oxide is a solid, sodium hydroxide is a solid or solution, sodium thallate(III) is a solid, and water is a liquid.
- Phenomena that occur
- During the reaction process, thallium(III) oxide gradually dissolves in the sodium hydroxide solution, then forms precipitated particles of sodium thallate(III) and creates water.
- There may be changes in the color of the solution during the reaction process.