The equation 2Tl2O3 + 6NaOH -> 2Na3TlO3 + 3H2O

  1. Detailed information on the chemical equation: 2Tl2O3 + 6NaOH -> 2Na3TlO3 + 3H2O
  • On the left side (reactants): 2 moles of Tl2O3 (Thallium(III) oxide) react with 6 moles of NaOH (Sodium hydroxide)
  • On the right side (products): 2 moles of Na3TlO3 (Sodium thallate(III)) and 3 moles of H2O (Water)
  1. Reaction conditions
  • This reaction needs to be carried out at high temperatures to promote the reaction.
  1. Reaction process
  • Thallium(III) oxide reacts with sodium hydroxide to form sodium thallate(III) and water.
  • Thallium(III) oxide is a solid, sodium hydroxide is a solid or solution, sodium thallate(III) is a solid, and water is a liquid.
  1. Phenomena that occur
  • During the reaction process, thallium(III) oxide gradually dissolves in the sodium hydroxide solution, then forms precipitated particles of sodium thallate(III) and creates water.
  • There may be changes in the color of the solution during the reaction process.

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